x^2+2x+14=5

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Solution for x^2+2x+14=5 equation:


Simplifying
x2 + 2x + 14 = 5

Reorder the terms:
14 + 2x + x2 = 5

Solving
14 + 2x + x2 = 5

Solving for variable 'x'.

Reorder the terms:
14 + -5 + 2x + x2 = 5 + -5

Combine like terms: 14 + -5 = 9
9 + 2x + x2 = 5 + -5

Combine like terms: 5 + -5 = 0
9 + 2x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-9' to each side of the equation.
9 + 2x + -9 + x2 = 0 + -9

Reorder the terms:
9 + -9 + 2x + x2 = 0 + -9

Combine like terms: 9 + -9 = 0
0 + 2x + x2 = 0 + -9
2x + x2 = 0 + -9

Combine like terms: 0 + -9 = -9
2x + x2 = -9

The x term is 2x.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2x + 1 + x2 = -9 + 1

Reorder the terms:
1 + 2x + x2 = -9 + 1

Combine like terms: -9 + 1 = -8
1 + 2x + x2 = -8

Factor a perfect square on the left side:
(x + 1)(x + 1) = -8

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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